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B  BDf>?"  v   0E?" !d  =E (2&f  0XI?" /  ?Exemple(2"b  c $?"    0H?"   =+ (2& B  HDԔ?"  &  <tP?"j 9 s ,$D  0 pMaille A B C D AD(2&f& &f   0V?"q SU 14(2&f.f ! 0,T?"q 4  SU 24(2&f.f " 0h_?"d'a SU 34(2&3.3 # 0c?"q SU 14(2&f.f|z   $  ,$D  0 % Hf>?"  & 0h?"% H  gU 1 +F(2&f.f&f ' 0X?"2E  wU 2 -V(2&f.f.f" ( 0xs?"!E  {U 3 +Z(2&3.3.f&f ) 0y?"E Z bE D(2&f&f&f * 0$~?"J  ;= 0(2"H  0޽h ? ̙33___PPT10+HDe' = @B D ' = @BA?%,( < +O%,( < +D' =%(D' =%(D1' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =-m6Bbox(in)*<3<*Dn' =%(D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*$%(D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*$D' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*$+? 0 j&b&44%(    6833>0e z6 ,$D  0 jRq:On peut crire la relation d une autre manire: \6(2$33 """4p  0ȍ~ x,$D 0 Attention!L criture ci-dessus ncessite un ordre strict des lettres! .J 2H&33x  B?"u,$D  0 jLa loi des mailles traduit l additivit des tensions.6(26$ HF    Rg w  Hf>?"   08?"% H  gU 1 +F(2&f.f&f  0P?"2E  wU 2 -V(2&f.f.f"   0?"!E  {U 3 +Z(2&3.3.f&f   0?"E Z bE D(2&f&f&f   0خ?"J  ;= 0(2"z a    ,$ 0B   HDf>?"'K 'B  HDf>?" X ` B  HD3>?" z2  <Ԕ?" zm nB  0DԔ?"3 c 3 nB  0DԔ?"X 3 X nB B 0DԔ?"X t2  6?"_ t2  6?"  t2  6?"[ Qt2  6?" Qz  <Ԕ?"   BZԔ?" z  <Ԕ?" p  0?"  =A (2&  0ĺ?"i n  =B (2&33  0ܾ?" e   =C (2&  0?"[  =D (2&fzB  <DԔ?") B  HDf>?"  B ! BDf>?"  v  " 0xƙ?" !d  =E (2&f # 0(ʙ?" /  ?Exemple(2"b $ c $?"   % 0HΙ?"   =+ (2& B & HDԔ?"  & ' <љ?"j 9 s ,$D  0 pMaille A B C D AD(2&f& &f ( 0tי?"q SU 14(2&f.f ) 0ۙ?"q 4  SU 24(2&f.f * 04ߙ?"d'a SU 34(2&3.3 + 0?"~G SU 14(2&f.ftz Js  ,  " ,$D 0 - Bf>?"Js  . 0?"L 0  {U 2 +Z(2&3.3.f&f / 0d?" -  eU 1F(2&f.f&f 0 0?"w :-  v+ E V(2&f&f&f&f 1 0?"l U2  9=(2" 2 0?"{ 7  eU 3F(2&3.3&f 3 <f?"a  6  ,$D 0 4 <x33>?" ( ,$D 0 WU C B + U B A + U A D = U C D(2& . . . 33& . 33. & . . f& . . . fH  0޽h ? ̙33___PPT10+ fVpD' = @B D' = @BA?%,( < +O%,( < +D{' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*Dn' =%(D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*,%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*,D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*,DX' =%(D' =%(D' =4@BBBB%(E' =1B B`BPB1:Bhidden*3>+B#style.visibility= `B<*3D' =1:Bvisible*o3>+B#style.visibility<*3%(D ' =%(D' =%(DZ' =A@BBB B0B%(D' =1:Bvisible*o3>+B#style.visibility<*4%(D' =-6B-randombar(horizontal)*<3<*4D' =%(D' =%(D@' =A@BB BB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =-o6Bdissolve*<3<*D{' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*D' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*++0+0 ++0+0 ++0+0 ++0+40 +=A 0 JB++(  R  C *APE01821_F@  0D ?"D3 D Exercice 2 (2 $  0@%?"g"m xBDterminer les tensions inconnues, en utilisant la loi des maillesC(2C l  6A?"pi z  j  ,~ ,$D 0t  6?" j  6L*?"9 ) ;1(2$  0H.?"5 _U ,$D 0 C Maille 1: (2 $"z %     % j ,$D  0   6`2  M00(2&$   67 ~  MU0(2&$   6<{ (  MU0(2&f$f  6@@%   MU0(2&$  6HE +  M10(2&$  6 JK+  M20(2&f$f  6,O+ Q M30(2&$  6Mj  M=0(2'$  6|Q  N- 0(2'$  6U q  N- 0(2'$  0?"6 S \/ ,$D 0  >A  ?3o? | 8  $D 0z 7   *O,$D  0t B 6?"7  B 6a?"*e  ;2(2$  0e?"%\E,$D 0 C Maille 2: (2 $  >A  ?3o? w8  $D  0  0?"&P Y,$D  0z %    " Z,$D  0  6j  M00(2&$  6o ~  MU0(2&33$33   6ht{ (  EU((2"  ! 6x%   MU0(2&3$3 " 6v +  M40(2&33$33 # 6@K+  E1((2"  $ 6+ Q M50(2&3$3 % 6̄j  M=0(2'$ & 6\  N- 0(2'$ ' 6x q  N- 0(2'$ ( >A  ?3o?Z8  $ 0 ) >A  ?3o?|8  $ 0 * >A  ?3o?C 8  $ 0" + 0 3?"l$D   05 0 0H  0޽h ? ̙33""___PPT10s"+D!' = @B D!' = @BA?%,( < +O%,( < +D' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<* D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<* D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =%(D1' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =-m6Bbox(in)*<3<* D' =%(D' =%(DK' =4@BBB B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =-6B+checkerboard(across)*<3<*D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D ' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+4 8?dCB0-#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*D' =%(D1' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =-m6Bbox(in)*<3<*D' =%(D1' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =-m6Bbox(in)*<3<*D' =%(D' =%(DK' =4@BBB B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =-6B+checkerboard(across)*<3<*D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*%(Dn' =%(D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*+%(D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*+D' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*++p+0+ 0 ++0+0 +# 0 (    s *4   ,$D 0 SPour un conducteur ohmique *, la caractristique courant-tension est une droite qui passe par l'origine des axes. * (ou rsistor linaire) 2$3$4$33"$3$$3$x    s *Z  F ,$D  0 ML'intensit du courant lectrique est proportionnelle la tension applique.N(2N$    T W3ԔԔ?La loi d'Ohm pour un conducteur ohmique :Times New Roman" 6  0?" dT '1)Caractristique courant - tension:h((2&&&&&y z  /?   / ? ,$D  0B  BDf>?"0   0@Ě?"   C Lgende : 2 &B  BDԔ?"[? B   BDԔ?" e   0ɚ?"/v UU A B4(2&.   0͚?"Q8  =I (2&33B  HDf>?"6B  HDf>?"'    0њ?"  =0 (2&1N  Y   h*  zB  <DԔ?" z  <?"Y '   0@֚?" Y  =R (2&B B HD>?"o r B  HD33>?"    6ښ?",$D  0 [Rq:R reprsente le coefficient directeur de la caractristique courant-tension du diple.l\(2$3f$3 $ $2 ZH  0޽h ? ̙33___PPT10+KpD' = @B D' = @BA?%,( < +O%,( < +DA' =%(D' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(Dn' =%(D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*D{' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*D' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*D{' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*D' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*++0+0 ++0+0 ++0+0 +7" 0 $%C(    s *XR X ,$D  0 8Rest une grandeur positive, caractristique du rsistor linaire; c est la rsistance lectrique du diple.Bn(2$fL $f   B?" i2)Loi d'Ohm:>(2$ $$P z     ,$D 0(  s *D pSi l'on adopte la convention rcepteur, les flches reprsentant la tension et le courant sont de sens opposs. :q(2($3G$f  N     T  c $Ԕ r B  3 X  H   C 1mK <   # V    6x=  OR2(2&,&JN        B   3 33[   rBCDEF33m @`   rBCDEF33k @`\ B  3 X  H  C 1mK <  # V   6 ;9  OR2(2&,f&fJN       B  3 33[   rBCDEF33m @`   rBCDEF33k @`\   B ?") TUA B4(2&.  6?"H   >I (2&33z G_   G_ ,$D 0N vB  vBT  c $ԔvB  6W, ?B"(2.  6,) ?A"(2.  6!H > I (2&33   6l$ > R (2&f ! 6( =U (2& " 6, O=2(2'& # s *P+ _  &PUA B en V I en A R en W (ohms)  20F2$,$$33$33$33$3  3 $ c $: ?"G0 g l,La loi d Ohm s crit:$(2 H  0޽h ? ̙33, $ ___PPT10 +bQ\ D ' == @B Dk ' = @BA?%,( < +O%,( < +D4' =%(D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =%(D' =%(D3' =4@BB BB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =-o6Bdissolve*<3<*D{' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<*D' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<*+8+0+0 + 0 ! (    DA ?Ԕ?C"t{8 $D 0z     ,$D  0|  8A  ?3?   0H 3 9 En posant 2 t  6L?"W4,$D  0 RRq 2:La loi d Ohm peut s crire aussi :D*(2$3f$3 # '  6(S?"RP,$D  0 t Gest la conductance du rsistor!(2!&3   6W?" N ,$D  0 n8Gs exprime en siemens ( S )(2"0  6p\?"u V ,$D  0 8Si Rs exprime en ohms ( W )4(2"#"H  0޽h ? ̙33 ___PPT10+@D'' h= @B D' = @BA?%,( < +O%,( < +D4' =%(D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*%(Dn' =%(D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =+4 8?dCB1+#ppt_w/2BCB#ppt_xB*Y3>B ppt_x<*D' =+4 8?\CB#ppt_yBCB#ppt_yB*Y3>B ppt_y<*D' =%(D' =%(D>' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =-m6Bbox(in)*<3<*D' =%(D' =%(D>' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =-m6Bbox(in)*<3<*D{' =%(D#' =%(D' =A@BBBB0B%(D' =1:Bvisible*o3>+B#style.visibility<* %(D' =+4 8?\CB#ppt_xBCB#ppt_xB*Y3>B ppt_x<* D' =+4 8?dCB1+#ppt_h/2BCB#ppt_yB*Y3>B ppt_y<* ++0+0 ++0+0 ++0+ 0 +% 0 ^V**(  z 0 =   = 0 ,$D  0T  c $Ԕ0 >   6(n  ;B(2$  6lrv  ;A(2$  6vT a =U (2&  6(zT a =G (2&3  6} T a =I (2&33   6P= J Q-4(2'&   6 u> K I=,(2#"z     > R ,$D 0T   c $Ԕ    6 :0 G =I (2&33  6o : G =R (2&3  6:G =U (2&  6 ;B(2$  6p ;A(2$  6؜[ O 5 M-0(2%$  6P#0 0 Q=4(2'&F Lo  Lo/  s *̥Lo wSi les flches reprsentant le courant et la tension lectrique sont dans le mme sens (convention gnrateur), on a: :x 2X $3f b  c $ A ?"Ak  0Ы?"$ E Attention! (2 $f* z       ,$D  0T  c $Ԕ  B  3  @? H  C 15 <  # B     6 V  OR2(2&,&PT    # =E#B  3 33[    rBCDEF33m @` B ! 3  @? H " C 15 < # # B    $ 6 V  OR2(2&,f&fPT    %# =E#B & 3 33[  ' rBCDEF33m @`  (B xBCDEF33k @`Q  ) B8?"" 1 b TUA B4(2&. * 6?"   >I (2&33H  0޽h ? ̙33  ___PPT10 +CCD ' = @B D ' = @BA?%,( < +O%,( < +D' =%(D' =%(D1' =4@BBBB%(D' =1:Bvisible*o3>+B#style.visibility<*%(D' =-m6Bbox(in)*<3<*Dn' =%(D' =%(D' =4@BBBB%(D' =1:Bvisible*o3>+